x^2-3x(2+x)=-x(3+2x)+15

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Solution for x^2-3x(2+x)=-x(3+2x)+15 equation:


Simplifying
x2 + -3x(2 + x) = -1x(3 + 2x) + 15
x2 + (2 * -3x + x * -3x) = -1x(3 + 2x) + 15
x2 + (-6x + -3x2) = -1x(3 + 2x) + 15

Reorder the terms:
-6x + x2 + -3x2 = -1x(3 + 2x) + 15

Combine like terms: x2 + -3x2 = -2x2
-6x + -2x2 = -1x(3 + 2x) + 15
-6x + -2x2 = (3 * -1x + 2x * -1x) + 15
-6x + -2x2 = (-3x + -2x2) + 15

Reorder the terms:
-6x + -2x2 = 15 + -3x + -2x2

Add '2x2' to each side of the equation.
-6x + -2x2 + 2x2 = 15 + -3x + -2x2 + 2x2

Combine like terms: -2x2 + 2x2 = 0
-6x + 0 = 15 + -3x + -2x2 + 2x2
-6x = 15 + -3x + -2x2 + 2x2

Combine like terms: -2x2 + 2x2 = 0
-6x = 15 + -3x + 0
-6x = 15 + -3x

Solving
-6x = 15 + -3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3x' to each side of the equation.
-6x + 3x = 15 + -3x + 3x

Combine like terms: -6x + 3x = -3x
-3x = 15 + -3x + 3x

Combine like terms: -3x + 3x = 0
-3x = 15 + 0
-3x = 15

Divide each side by '-3'.
x = -5

Simplifying
x = -5

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